The random variable X has the pdf:
f(x)=0.3 for x=1,4 and f(x)=0.2 for x=2,3.
That is, the pdf is represented in the following table.
| x | 1.00 | 2.00 | 3.00 | 4.00 |
| f(x) | 0.30 | 0.20 | 0.20 | 0.30 |
- Please calculate P(X>2.1)
Find all cases of X>2.1, then add up their probabilities.
- 0.5
This is a discrete random variable. So you need to find the cases for X>2.1, and add up the probabilities of those cases.
There are two possible values for X>2.1: X=3 and X=4.
Hence the probability is f(3)+f(4)=0.2+0.3 =0.5